• 0
Votes
name

A PHP Error was encountered

Severity: Notice

Message: Undefined index: userid

Filename: views/question.php

Line Number: 195

Backtrace:

File: /home/u125378470/domains/lawhelpguru.org/public_html/application/views/question.php
Line: 195
Function: _error_handler

File: /home/u125378470/domains/lawhelpguru.org/public_html/application/controllers/Questions.php
Line: 416
Function: view

File: /home/u125378470/domains/lawhelpguru.org/public_html/index.php
Line: 315
Function: require_once

name Punditsdkoslkdosdkoskdo

How can I open a URL in Android's web browser from my application?

<button aria-describedby="--stacks-s-tooltip-issrz8uw" aria-label="Bookmark (224)" aria-pressed="false" class="js-bookmark-btn s-btn s-btn__unset c-pointer py4 js-gps-track" data-controller="s-tooltip" data-gps-track="post.click({ item: 1, priv: 0, post_type: 1 })" data-s-tooltip-placement="right" data-selected-classes="fc-yellow-600"></button>

<button aria-describedby="--stacks-s-tooltip-issrz8uw" aria-label="Bookmark (224)" aria-pressed="false" class="js-bookmark-btn s-btn s-btn__unset c-pointer py4 js-gps-track" data-controller="s-tooltip" data-gps-track="post.click({ item: 1, priv: 0, post_type: 1 })" data-s-tooltip-placement="right" data-selected-classes="fc-yellow-600">224</button>

<svg aria-hidden="true" class="mln2 mr0 svg-icon iconHistory" height="18" viewbox="0 0 19 18" width="19"></svg>

 

How to open an URL from code in the built-in web browser rather than within my application?

I tried this:

try {
    Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(download_link));
    startActivity(myIntent);
} catch (ActivityNotFoundException e) {
    Toast.makeText(this, "No application can handle this request."
        + " Please install a webbrowser",  Toast.LENGTH_LONG).show();
    e.printStackTrace();
}

but I got an Exception:

No activity found to handle Intent{action=android.intent.action.VIEW data =www.google.com